.25x^2+5x=0

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Solution for .25x^2+5x=0 equation: 



.25x^2+5x=0

a = .25; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·.25·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*.25}=\frac{-10}{0.5}
=-20
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*.25}=\frac{0}{0.5}
=0
$

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